@ughaibu,
ughaibu;133556 wrote:If there is such an x, but there isn't such an x because the empty set is the set of all such x. I still dont see the problem, if you've proved that all x not equal to themselves aren't equal to themselves, there's no conflict with the empty set equaling itself. Is there?
The empty set is defined as that set which has no elements...{x:~(x=x)}.
ughaibu,
"I still dont see the problem, if you've proved that all
x not equal to themselves aren't equal to themselves, there's no conflict with the empty set equaling itself."
I did not prove that 'all x not equal to themselves aren't equal to themselves'.
I did prove that the described individual object (the x:~(x=x)), does not equal itself.
(the x:~(x=x)) is a member of {x:~(x=x)}, is false!
It is false to say that the null set contains non-existent objects.
There are no non-existent objects at all...they do not exist.
ughaibu,
"there's no conflict with the empty set equaling itself. Is there?"
As I have already said, the null set is equal to itself and it does exist.
The null object is not the same as the null set.